python递归实现循环遍历多层级字典

class DictTraversal:def __init__(self, dictionary):self.dictionary = dictionarydef traverse(self, dictionary=None):if dictionary is None:dictionary = self.dictionaryfor key, value in dictionary.items():if isinstance(value, dict):self.trav 0 Comments 

class DictTraversal:def __init__(self, dictionary):self.dictionary = dictionarydef traverse(self, dictionary=None):if dictionary is None:dictionary = self.dictionaryfor key, value in dictionary.items():if isinstance(value, dict):self.traverse(value)  # 递归调用遍历子字典else:print(key, value)  # 处理字典的键值对# 示例用法
my_dict = {'key1': 'value1','key2': {'key3': 'value3','key4': {'key5': 'value5'}}
}dt = DictTraversal(my_dict)
dt.traverse()# 输出结果
key1 value1
key3 value3
key5 value5

        这个类的traverse方法会遍历多层级的字典，并输出每个键值对。递归函数的关键是判断每个值是否是字典，如果是字典则递归调用遍历子字典，否则直接处理键值对。使用这个类，可以灵活地遍历多层级字典的所有元素。

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